(l^2-3l+2)x^2+(l-2)x+3=0

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Solution for (l^2-3l+2)x^2+(l-2)x+3=0 equation: 


Simplifying
(l2 + -3l + 2) * x2 + (l + -2) * x + 3 = 0

Reorder the terms:
(2 + -3l + l2) * x2 + (l + -2) * x + 3 = 0

Reorder the terms for easier multiplication:
x2(2 + -3l + l2) + (l + -2) * x + 3 = 0
(2 * x2 + -3l * x2 + l2 * x2) + (l + -2) * x + 3 = 0

Reorder the terms:
(-3lx2 + l2x2 + 2x2) + (l + -2) * x + 3 = 0
(-3lx2 + l2x2 + 2x2) + (l + -2) * x + 3 = 0

Reorder the terms:
-3lx2 + l2x2 + 2x2 + (-2 + l) * x + 3 = 0

Reorder the terms for easier multiplication:
-3lx2 + l2x2 + 2x2 + x(-2 + l) + 3 = 0
-3lx2 + l2x2 + 2x2 + (-2 * x + l * x) + 3 = 0

Reorder the terms:
-3lx2 + l2x2 + 2x2 + (lx + -2x) + 3 = 0
-3lx2 + l2x2 + 2x2 + (lx + -2x) + 3 = 0

Reorder the terms:
3 + lx + -3lx2 + l2x2 + -2x + 2x2 = 0

Solving
3 + lx + -3lx2 + l2x2 + -2x + 2x2 = 0

Solving for variable 'l'.

The solution to this equation could not be determined.

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